If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x^2+12x-11=0
a = 4; b = 12; c = -11;
Δ = b2-4ac
Δ = 122-4·4·(-11)
Δ = 320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{320}=\sqrt{64*5}=\sqrt{64}*\sqrt{5}=8\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-8\sqrt{5}}{2*4}=\frac{-12-8\sqrt{5}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+8\sqrt{5}}{2*4}=\frac{-12+8\sqrt{5}}{8} $
| -7x-2x=99 | | 21462/x*2=95 | | 9x-3x+12=72 | | (7x-4)=(8x-23) | | 5-5p^2=-95 | | -2(b-19.38)=17.84 | | 3+2n+1+2n=3*8 | | 21462/x*x=95 | | 2x-x+20=60 | | 80x+1350=2310 | | -x+4+22=9 | | q/5+68=75 | | 21462/x2=95 | | 6x^2-7x+15=0 | | 3(y+14)=60 | | -71=-6+5j | | 3(4n-5)=6(n+3) | | 9(b+11)=-144 | | 16-2(3x+5)=38 | | 5x+23=3x+33 | | 24+x+24=62 | | −3−2x2=−(x−2) | | 36+13m=244 | | -2.1x=6.3 | | 29n-108=153 | | 2(w-1)=9w+47 | | |3q+6|=5q+2 | | 4x–8+2x=11+5 | | 99=0.75x | | −18+2x=13(18+6x)−4 | | 2(4)^2x=64 | | 4j−–4=16 |