4x2+13x+3=

Solution for 4x2+13x+3= equation:

4x^2+13x+3=

We move all terms to the left:

4x^2+13x+3-()=0

We add all the numbers together, and all the variables

4x^2+13x=0

a = 4; b = 13; c = 0;
Δ = b2-4ac
Δ = 132-4·4·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-13}{2*4}=\frac{-26}{8}
=-3+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+13}{2*4}=\frac{0}{8}
=0
$