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4x^2+13x-41300=0
a = 4; b = 13; c = -41300;
Δ = b2-4ac
Δ = 132-4·4·(-41300)
Δ = 660969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{660969}=813$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-813}{2*4}=\frac{-826}{8} =-103+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+813}{2*4}=\frac{800}{8} =100 $
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