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4x^2+13x-41303=0
a = 4; b = 13; c = -41303;
Δ = b2-4ac
Δ = 132-4·4·(-41303)
Δ = 661017
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{661017}}{2*4}=\frac{-13-\sqrt{661017}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{661017}}{2*4}=\frac{-13+\sqrt{661017}}{8} $
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