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4x^2+13x=4x+35
We move all terms to the left:
4x^2+13x-(4x+35)=0
We get rid of parentheses
4x^2+13x-4x-35=0
We add all the numbers together, and all the variables
4x^2+9x-35=0
a = 4; b = 9; c = -35;
Δ = b2-4ac
Δ = 92-4·4·(-35)
Δ = 641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{641}}{2*4}=\frac{-9-\sqrt{641}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{641}}{2*4}=\frac{-9+\sqrt{641}}{8} $
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