4x2+160x+1600=0

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Solution for 4x2+160x+1600=0 equation: 



4x^2+160x+1600=0

a = 4; b = 160; c = +1600;
Δ = b2-4ac
Δ = 1602-4·4·1600
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-160}{8}=-20$

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