4x2+16x+20=4

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Solution for 4x2+16x+20=4 equation: 



4x^2+16x+20=4

We move all terms to the left:

4x^2+16x+20-(4)=0

We add all the numbers together, and all the variables

4x^2+16x+16=0

a = 4; b = 16; c = +16;
Δ = b2-4ac
Δ = 162-4·4·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-16}{8}=-2$

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