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4x^2+17x+13=0
a = 4; b = 17; c = +13;
Δ = b2-4ac
Δ = 172-4·4·13
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-9}{2*4}=\frac{-26}{8} =-3+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+9}{2*4}=\frac{-8}{8} =-1 $
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