4x2+17x+15=0

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Solution for 4x2+17x+15=0 equation:



4x^2+17x+15=0
a = 4; b = 17; c = +15;
Δ = b2-4ac
Δ = 172-4·4·15
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-7}{2*4}=\frac{-24}{8} =-3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+7}{2*4}=\frac{-10}{8} =-1+1/4 $

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