4x2+18x=162

Solution for 4x2+18x=162 equation:

4x^2+18x=162

We move all terms to the left:

4x^2+18x-(162)=0

a = 4; b = 18; c = -162;
Δ = b2-4ac
Δ = 182-4·4·(-162)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-54}{2*4}=\frac{-72}{8}
=-9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+54}{2*4}=\frac{36}{8}
=4+1/2
$