If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x^2+20x+16=0.
a = 4; b = 20; c = +16;
Δ = b2-4ac
Δ = 202-4·4·16
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-12}{2*4}=\frac{-32}{8} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+12}{2*4}=\frac{-8}{8} =-1 $
| (5+7i)-(-8-3i)=0 | | 0.52=327000/x | | x/12=1810 | | 6x+11=4-5x | | 3(2+y)=2y-4 | | N=300(3)t | | 5y/2=5/3 | | 0.5=-15.5+(-3.6x)+1.8x | | ¼+12=½x+10 | | (X+y)/2=27.5 | | 4w+5×2w=280 | | -7×(x-18)=84 | | -4K+2(5k-6)-3k=39 | | -4K+10k-12-3k=39 | | 40(x)+8(1.5x)=1300 | | 7x+5+x-7=180 | | 2|3-x|-7=3 | | F(x)=0,5x+3 | | 8n+12+4n+8=13n-15 | | 1/3x=−1/4x−10 | | 36-10(n+4)=6 | | 2x-3(x-2)=9 | | 6x+3=6x-2-x | | -5x-2(10)=24 | | -3(10)+2y=56 | | -3x+2(10)=56 | | -16t^2+(128)T=0 | | 21/h=28/5 | | 9-4n=3n | | -16t^2+(128)T=240 | | 7(2.5g+7)-4=-25 | | 8x=980 |