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4x^2+21x-25=0
a = 4; b = 21; c = -25;
Δ = b2-4ac
Δ = 212-4·4·(-25)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-29}{2*4}=\frac{-50}{8} =-6+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+29}{2*4}=\frac{8}{8} =1 $
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