If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x^2+24x+11=0
a = 4; b = 24; c = +11;
Δ = b2-4ac
Δ = 242-4·4·11
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-20}{2*4}=\frac{-44}{8} =-5+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+20}{2*4}=\frac{-4}{8} =-1/2 $
| 42-4xx=2 | | x=-51x | | 2x+18=58−8x | | 3/2b-41/3=3/2+3/4b | | 11/2b-41/3=11/2+3/4b | | 1+3m+5=m+18-4 | | 2x²+9x+9=0 | | 3m/5-1=m/3+3/5 | | 3x+11=41−2x | | 5d÷3+1=d÷6+3 | | (4+2b)-(3-3b)= | | 122•x=180 | | 74x=180 | | 24+2x=6 | | x+x+x+3x-3-4-5-6-7-8=0 | | 4.12+2k=9.52 | | 25x/4=45 | | 8-5c=-77 | | 14-2m=10 | | 4g-13=-0.6 | | 1/4x-10=6 | | c+27/7=9 | | 15=9w-4w | | 3x=2x-500 | | 5(r−73)=40 | | 4=k-+24/8 | | 5x+29=8-2x | | 88=g/9+80 | | 1.4/6=x/15 | | f/3=25=35 | | 1.6/6=x/21 | | 4g-16=12 |