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4x^2+24x=45
We move all terms to the left:
4x^2+24x-(45)=0
a = 4; b = 24; c = -45;
Δ = b2-4ac
Δ = 242-4·4·(-45)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-36}{2*4}=\frac{-60}{8} =-7+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+36}{2*4}=\frac{12}{8} =1+1/2 $
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