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4x^2+29x-24=0
a = 4; b = 29; c = -24;
Δ = b2-4ac
Δ = 292-4·4·(-24)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-35}{2*4}=\frac{-64}{8} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+35}{2*4}=\frac{6}{8} =3/4 $
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