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4x^2+2x=272.
We move all terms to the left:
4x^2+2x-(272.)=0
We add all the numbers together, and all the variables
4x^2+2x-272=0
a = 4; b = 2; c = -272;
Δ = b2-4ac
Δ = 22-4·4·(-272)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-66}{2*4}=\frac{-68}{8} =-8+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+66}{2*4}=\frac{64}{8} =8 $
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