4x2+36x+56=0

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Solution for 4x2+36x+56=0 equation:



4x^2+36x+56=0
a = 4; b = 36; c = +56;
Δ = b2-4ac
Δ = 362-4·4·56
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-20}{2*4}=\frac{-56}{8} =-7 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+20}{2*4}=\frac{-16}{8} =-2 $

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