4x2+3x+12=3-3x

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Solution for 4x2+3x+12=3-3x equation: 



4x^2+3x+12=3-3x

We move all terms to the left:

4x^2+3x+12-(3-3x)=0

We add all the numbers together, and all the variables

4x^2+3x-(-3x+3)+12=0

We get rid of parentheses

4x^2+3x+3x-3+12=0

We add all the numbers together, and all the variables

4x^2+6x+9=0

a = 4; b = 6; c = +9;
Δ = b2-4ac
Δ = 62-4·4·9
Δ = -108
Delta is less than zero, so there is no solution for the equation

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