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4x^2+3x^2=
We move all terms to the left:
4x^2+3x^2-()=0
We add all the numbers together, and all the variables
7x^2=0
a = 7; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·7·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{14}=0$
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