4x2+56x=93

Solution for 4x2+56x=93 equation:

4x^2+56x=93

We move all terms to the left:

4x^2+56x-(93)=0

a = 4; b = 56; c = -93;
Δ = b2-4ac
Δ = 562-4·4·(-93)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4624}=68$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-68}{2*4}=\frac{-124}{8}
=-15+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+68}{2*4}=\frac{12}{8}
=1+1/2
$