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4x^2+5=2x+1
We move all terms to the left:
4x^2+5-(2x+1)=0
We get rid of parentheses
4x^2-2x-1+5=0
We add all the numbers together, and all the variables
4x^2-2x+4=0
a = 4; b = -2; c = +4;
Δ = b2-4ac
Δ = -22-4·4·4
Δ = -60
Delta is less than zero, so there is no solution for the equation
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