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4x^2+5x+8=2x^2-2x+7
We move all terms to the left:
4x^2+5x+8-(2x^2-2x+7)=0
We get rid of parentheses
4x^2-2x^2+5x+2x-7+8=0
We add all the numbers together, and all the variables
2x^2+7x+1=0
a = 2; b = 7; c = +1;
Δ = b2-4ac
Δ = 72-4·2·1
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{41}}{2*2}=\frac{-7-\sqrt{41}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{41}}{2*2}=\frac{-7+\sqrt{41}}{4} $
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