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4x^2+5x-84=0
a = 4; b = 5; c = -84;
Δ = b2-4ac
Δ = 52-4·4·(-84)
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-37}{2*4}=\frac{-42}{8} =-5+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+37}{2*4}=\frac{32}{8} =4 $
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