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4x^2+5x=7(x1)
We move all terms to the left:
4x^2+5x-(7(x1))=0
determiningTheFunctionDomain 4x^2+5x-7x1=0
We add all the numbers together, and all the variables
4x^2-2x=0
a = 4; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·4·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*4}=\frac{0}{8} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*4}=\frac{4}{8} =1/2 $
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