4x2+60x-1080=0

Solution for 4x2+60x-1080=0 equation:

4x^2+60x-1080=0

a = 4; b = 60; c = -1080;
Δ = b2-4ac
Δ = 602-4·4·(-1080)
Δ = 20880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{20880}=\sqrt{144*145}=\sqrt{144}*\sqrt{145}=12\sqrt{145}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-12\sqrt{145}}{2*4}=\frac{-60-12\sqrt{145}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+12\sqrt{145}}{2*4}=\frac{-60+12\sqrt{145}}{8}
$