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4x^2+64x+240=0
a = 4; b = 64; c = +240;
Δ = b2-4ac
Δ = 642-4·4·240
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-16}{2*4}=\frac{-80}{8} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+16}{2*4}=\frac{-48}{8} =-6 $
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