4x2+68x-111=0

Solution for 4x2+68x-111=0 equation:

4x^2+68x-111=0

a = 4; b = 68; c = -111;
Δ = b2-4ac
Δ = 682-4·4·(-111)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(68)-80}{2*4}=\frac{-148}{8}
=-18+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(68)+80}{2*4}=\frac{12}{8}
=1+1/2
$