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4x^2+6=(2+3)
We move all terms to the left:
4x^2+6-((2+3))=0
We add all the numbers together, and all the variables
4x^2+6-(5)=0
We add all the numbers together, and all the variables
4x^2+1=0
a = 4; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·4·1
Δ = -16
Delta is less than zero, so there is no solution for the equation
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