4x2+72x+320=0

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Solution for 4x2+72x+320=0 equation:



4x^2+72x+320=0
a = 4; b = 72; c = +320;
Δ = b2-4ac
Δ = 722-4·4·320
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-8}{2*4}=\frac{-80}{8} =-10 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+8}{2*4}=\frac{-64}{8} =-8 $

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