4x2+7x-15=0

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Solution for 4x2+7x-15=0 equation:



4x^2+7x-15=0
a = 4; b = 7; c = -15;
Δ = b2-4ac
Δ = 72-4·4·(-15)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-17}{2*4}=\frac{-24}{8} =-3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+17}{2*4}=\frac{10}{8} =1+1/4 $

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