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4x^2+81=36x
We move all terms to the left:
4x^2+81-(36x)=0
a = 4; b = -36; c = +81;
Δ = b2-4ac
Δ = -362-4·4·81
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{36}{8}=4+1/2$
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