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4x^2+8x-252=0
a = 4; b = 8; c = -252;
Δ = b2-4ac
Δ = 82-4·4·(-252)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4096}=64$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-64}{2*4}=\frac{-72}{8} =-9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+64}{2*4}=\frac{56}{8} =7 $
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