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4x^2+90x-684=0
a = 4; b = 90; c = -684;
Δ = b2-4ac
Δ = 902-4·4·(-684)
Δ = 19044
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{19044}=138$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(90)-138}{2*4}=\frac{-228}{8} =-28+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(90)+138}{2*4}=\frac{48}{8} =6 $
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