4x2-10x+6=0

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Solution for 4x2-10x+6=0 equation: 



4x^2-10x+6=0

a = 4; b = -10; c = +6;
Δ = b2-4ac
Δ = -102-4·4·6
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2}{2*4}=\frac{8}{8}
=1
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2}{2*4}=\frac{12}{8}
=1+1/2
$

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