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4x^2-130=-6x
We move all terms to the left:
4x^2-130-(-6x)=0
We get rid of parentheses
4x^2+6x-130=0
a = 4; b = 6; c = -130;
Δ = b2-4ac
Δ = 62-4·4·(-130)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-46}{2*4}=\frac{-52}{8} =-6+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+46}{2*4}=\frac{40}{8} =5 $
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