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4x^2-15x+11=6x+6
We move all terms to the left:
4x^2-15x+11-(6x+6)=0
We get rid of parentheses
4x^2-15x-6x-6+11=0
We add all the numbers together, and all the variables
4x^2-21x+5=0
a = 4; b = -21; c = +5;
Δ = b2-4ac
Δ = -212-4·4·5
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-19}{2*4}=\frac{2}{8} =1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+19}{2*4}=\frac{40}{8} =5 $
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