4x2-15x+9=0

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Solution for 4x2-15x+9=0 equation: 



4x^2-15x+9=0

a = 4; b = -15; c = +9;
Δ = b2-4ac
Δ = -152-4·4·9
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-9}{2*4}=\frac{6}{8}
=3/4
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+9}{2*4}=\frac{24}{8}
=3
$

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