4x2-1=-8x

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Solution for 4x2-1=-8x equation:



4x^2-1=-8x
We move all terms to the left:
4x^2-1-(-8x)=0
We get rid of parentheses
4x^2+8x-1=0
a = 4; b = 8; c = -1;
Δ = b2-4ac
Δ = 82-4·4·(-1)
Δ = 80
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{80}=\sqrt{16*5}=\sqrt{16}*\sqrt{5}=4\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{5}}{2*4}=\frac{-8-4\sqrt{5}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{5}}{2*4}=\frac{-8+4\sqrt{5}}{8} $

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