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4x^2-21x-324=0
a = 4; b = -21; c = -324;
Δ = b2-4ac
Δ = -212-4·4·(-324)
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5625}=75$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-75}{2*4}=\frac{-54}{8} =-6+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+75}{2*4}=\frac{96}{8} =12 $
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