4x2-27x-40=0

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Solution for 4x2-27x-40=0 equation:



4x^2-27x-40=0
a = 4; b = -27; c = -40;
Δ = b2-4ac
Δ = -272-4·4·(-40)
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1369}=37$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-37}{2*4}=\frac{-10}{8} =-1+1/4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+37}{2*4}=\frac{64}{8} =8 $

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