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4x^2-28x+49-125=9x^2+12x+4
We move all terms to the left:
4x^2-28x+49-125-(9x^2+12x+4)=0
We add all the numbers together, and all the variables
4x^2-28x-(9x^2+12x+4)-76=0
We get rid of parentheses
4x^2-9x^2-28x-12x-4-76=0
We add all the numbers together, and all the variables
-5x^2-40x-80=0
a = -5; b = -40; c = -80;
Δ = b2-4ac
Δ = -402-4·(-5)·(-80)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{40}{-10}=-4$
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