4x2-28x=48=

Solution for 4x2-28x=48= equation:

4x^2-28x=48=

We move all terms to the left:

4x^2-28x-(48)=0

a = 4; b = -28; c = -48;
Δ = b2-4ac
Δ = -282-4·4·(-48)
Δ = 1552
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1552}=\sqrt{16*97}=\sqrt{16}*\sqrt{97}=4\sqrt{97}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-4\sqrt{97}}{2*4}=\frac{28-4\sqrt{97}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+4\sqrt{97}}{2*4}=\frac{28+4\sqrt{97}}{8}
$