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4x^2-2x+1=2x
We move all terms to the left:
4x^2-2x+1-(2x)=0
We add all the numbers together, and all the variables
4x^2-4x+1=0
a = 4; b = -4; c = +1;
Δ = b2-4ac
Δ = -42-4·4·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{4}{8}=1/2$
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