If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x^2-2x-2=
We move all terms to the left:
4x^2-2x-2-()=0
We add all the numbers together, and all the variables
4x^2-2x=0
a = 4; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·4·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*4}=\frac{0}{8} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*4}=\frac{4}{8} =1/2 $
| 3-4n+2=-7 | | (4t-1)(5-t)(8t+5)=0 | | 4/5x-10-6/2=3/5x-10 | | 22-11p=3 | | 11a+3a+a-12a=18 | | -16=02b | | 6a-4a+4a-2=10 | | 6z-3z-z+z=12 | | 18k=2 | | 112+2h=972 | | 2x^2+10=106 | | 2(3x+5)=2(2x-3)+x | | 2m^2+59m-30=0 | | 2n-2n+3n-1=20 | | 910=5(x+19) | | 3(x+5)=7(x+4) | | 5x-2x-2=1 | | 10+2n=4n-2 | | 2c-2c+c-1=11 | | 10+6n=4-2n | | 2c+4c-6c+5c=10 | | 9j+2j-4j=7 | | 9j+2j−4j=7j=0j=4j=2j=1 | | 6x-4(2x+2)=4x | | 3^12x=81^2x-4 | | a−a+4a−3a=10a=9a=13a=3a=10 | | u-u+u-u+4u=16 | | u−u+u−u+4u=16 | | 0.5*t7/8=5 | | 5(0)+9y=10 | | 5=2x+7=13 | | 86=4/5x-10 |