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4x^2-30x-16=0
a = 4; b = -30; c = -16;
Δ = b2-4ac
Δ = -302-4·4·(-16)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-34}{2*4}=\frac{-4}{8} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+34}{2*4}=\frac{64}{8} =8 $
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