4x2-328=72

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Solution for 4x2-328=72 equation:



4x^2-328=72
We move all terms to the left:
4x^2-328-(72)=0
We add all the numbers together, and all the variables
4x^2-400=0
a = 4; b = 0; c = -400;
Δ = b2-4ac
Δ = 02-4·4·(-400)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80}{2*4}=\frac{-80}{8} =-10 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80}{2*4}=\frac{80}{8} =10 $

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