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4x^2-37x+9=0
a = 4; b = -37; c = +9;
Δ = b2-4ac
Δ = -372-4·4·9
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-35}{2*4}=\frac{2}{8} =1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+35}{2*4}=\frac{72}{8} =9 $
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