4x2-4x=11

Solution for 4x2-4x=11 equation:

4x^2-4x=11

We move all terms to the left:

4x^2-4x-(11)=0

a = 4; b = -4; c = -11;
Δ = b2-4ac
Δ = -42-4·4·(-11)
Δ = 192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{192}=\sqrt{64*3}=\sqrt{64}*\sqrt{3}=8\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-8\sqrt{3}}{2*4}=\frac{4-8\sqrt{3}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+8\sqrt{3}}{2*4}=\frac{4+8\sqrt{3}}{8}
$