4x2-6x-0=0

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Solution for 4x2-6x-0=0 equation:



4x^2-6x-0=0
We add all the numbers together, and all the variables
4x^2-6x=0
a = 4; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·4·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*4}=\frac{0}{8} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*4}=\frac{12}{8} =1+1/2 $

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