4x2-6x=14

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Solution for 4x2-6x=14 equation:



4x^2-6x=14
We move all terms to the left:
4x^2-6x-(14)=0
a = 4; b = -6; c = -14;
Δ = b2-4ac
Δ = -62-4·4·(-14)
Δ = 260
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{260}=\sqrt{4*65}=\sqrt{4}*\sqrt{65}=2\sqrt{65}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{65}}{2*4}=\frac{6-2\sqrt{65}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{65}}{2*4}=\frac{6+2\sqrt{65}}{8} $

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